Box U contains 14 black beads and 4 pink beads. Box V contains 84 black beads and 34 pink beads. How many pink beads and black beads must be moved from Box V to put into Box U so that 50% of the beads in Box A are black and 80% of the beads in Box V are black?
|
Box U |
Box V |
|
Black beads |
Pink beads |
Black beads |
Pink beads |
Before |
14 |
4 |
84 |
34 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
4 p |
1 p |
50% =
50100 = 12
80% =
80100 = 45
Number of black beads = 14 + 84 = 98
Number of pink beads = 4 + 34 = 38
1 u + 4 p = 98 --- (1)
1 u + 1 p = 38 ---(2)
(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 98 - 38
4 p - 1 p = 60
3 p = 60
1 p = 60 ÷ 3 = 20
From (2):
1 u + 1 p = 38
1 u + 1 x 20 = 38
1 u + 20 = 38
1 u = 38 - 20 = 18
Number of pink beads to be moved from Box V to Box U
= 34 - 1 p
= 34 - 1 x 20
= 34 - 20
= 14
Number of black beads to be moved from Box V to Box U
= 1 u - 14
= 18 - 14
= 4
Total number of pink and black beads to be moved from Box V to Box U
= 14 + 4
= 18
Answer(s): 18