Crate K contains 11 yellow beads and 6 brown beads. Crate L contains 48 yellow beads and 25 brown beads. How many brown beads and yellow beads must be removed from Crate L to put into Crate K so that 50% of the beads in Crate A are yellow and 75% of the beads in Crate L are yellow?

	Crate K		Crate L
	Yellow beads	Brown beads	Yellow beads	Brown beads
Before	11	6	48	25
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of yellow beads = 11 + 48 = 59 

Number of brown beads = 6 + 25 = 31 

1 u + 3 p = 59 --- (1)

1 u + 1 p = 31 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 59 - 31
3 p - 1 p = 28
2 p = 28

1 p = 28 ÷ 2 = 14

From (2):
1 u + 1 p = 31
1 u + 1 x 14 = 31
1 u + 14 = 31

1 u = 31 - 14 = 17

Number of brown beads to be removed from Crate L to Crate K
= 25 - 1 p
= 25 - 1 x 14
= 25 - 14
= 11

Number of yellow beads to be removed from Crate L to Crate K
= 1 u - 11
= 17 - 11
= 6

Total number of brown and yellow beads to be removed from Crate L to Crate K
= 11 + 6
= 17

Answer(s): 17