Crate V contains 12 silver marbles and 17 blue marbles. Crate W contains 24 silver marbles and 7 blue marbles. How many blue marbles and silver marbles must be moved from Crate W to put into Crate V so that 50% of the marbles in Crate A are silver and 80% of the marbles in Crate W are silver?
|
Crate V |
Crate W |
|
Silver marbles |
Blue marbles |
Silver marbles |
Blue marbles |
Before |
12 |
17 |
24 |
7 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
4 p |
1 p |
50% =
50100 = 12
80% =
80100 = 45
Number of silver marbles = 12 + 24 = 36
Number of blue marbles = 17 + 7 = 24
1 u + 4 p = 36 --- (1)
1 u + 1 p = 24 ---(2)
(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 36 - 24
4 p - 1 p = 12
3 p = 12
1 p = 12 ÷ 3 = 4
From (2):
1 u + 1 p = 24
1 u + 1 x 4 = 24
1 u + 4 = 24
1 u = 24 - 4 = 20
Number of blue marbles to be moved from Crate W to Crate V
= 7 - 1 p
= 7 - 1 x 4
= 7 - 4
= 3
Number of silver marbles to be moved from Crate W to Crate V
= 1 u - 12
= 20 - 12
= 8
Total number of blue and silver marbles to be moved from Crate W to Crate V
= 3 + 8
= 11
Answer(s): 11