Container H contains 3 red beads and 14 brown beads. Container J contains 36 red beads and 11 brown beads. How many brown beads and red beads must be transferred from Container J to put into Container H so that 50% of the beads in Container A are red and 75% of the beads in Container J are red?

	Container H		Container J
	Red beads	Brown beads	Red beads	Brown beads
Before	3	14	36	11
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of red beads = 3 + 36 = 39 

Number of brown beads = 14 + 11 = 25 

1 u + 3 p = 39 --- (1)

1 u + 1 p = 25 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 39 - 25
3 p - 1 p = 14
2 p = 14

1 p = 14 ÷ 2 = 7

From (2):
1 u + 1 p = 25
1 u + 1 x 7 = 25
1 u + 7 = 25

1 u = 25 - 7 = 18

Number of brown beads to be transferred from Container J to Container H
= 11 - 1 p
= 11 - 1 x 7
= 11 - 7
= 4

Number of red beads to be transferred from Container J to Container H
= 1 u - 3
= 18 - 3
= 15

Total number of brown and red beads to be transferred from Container J to Container H
= 4 + 15
= 19

Answer(s): 19