Crate M contains 2 red beads and 7 silver beads. Crate N contains 44 red beads and 19 silver beads. How many silver beads and red beads must be moved from Crate N to put into Crate M so that 50% of the beads in Crate A are red and 75% of the beads in Crate N are red?

	Crate M		Crate N
	Red beads	Silver beads	Red beads	Silver beads
Before	2	7	44	19
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of red beads = 2 + 44 = 46 

Number of silver beads = 7 + 19 = 26 

1 u + 3 p = 46 --- (1)

1 u + 1 p = 26 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 46 - 26
3 p - 1 p = 20
2 p = 20

1 p = 20 ÷ 2 = 10

From (2):
1 u + 1 p = 26
1 u + 1 x 10 = 26
1 u + 10 = 26

1 u = 26 - 10 = 16

Number of silver beads to be moved from Crate N to Crate M
= 19 - 1 p
= 19 - 1 x 10
= 19 - 10
= 9

Number of red beads to be moved from Crate N to Crate M
= 1 u - 2
= 16 - 2
= 14

Total number of silver and red beads to be moved from Crate N to Crate M
= 9 + 14
= 23

Answer(s): 23