Crate K contains 2 red beads and 17 silver beads. Crate L contains 35 red beads and 8 silver beads. How many silver beads and red beads must be moved from Crate L to put into Crate K so that 50% of the beads in Crate A are red and 75% of the beads in Crate L are red?

	Crate K		Crate L
	Red beads	Silver beads	Red beads	Silver beads
Before	2	17	35	8
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of red beads = 2 + 35 = 37 

Number of silver beads = 17 + 8 = 25 

1 u + 3 p = 37 --- (1)

1 u + 1 p = 25 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 37 - 25
3 p - 1 p = 12
2 p = 12

1 p = 12 ÷ 2 = 6

From (2):
1 u + 1 p = 25
1 u + 1 x 6 = 25
1 u + 6 = 25

1 u = 25 - 6 = 19

Number of silver beads to be moved from Crate L to Crate K
= 8 - 1 p
= 8 - 1 x 6
= 8 - 6
= 2

Number of red beads to be moved from Crate L to Crate K
= 1 u - 2
= 19 - 2
= 17

Total number of silver and red beads to be moved from Crate L to Crate K
= 2 + 17
= 19

Answer(s): 19