Box R contains 2 purple marbles and 4 black marbles. Box S contains 20 purple marbles and 12 black marbles. How many black marbles and purple marbles must be transferred from Box S to put into Box R so that 50% of the marbles in Box A are purple and 80% of the marbles in Box S are purple?
|
Box R |
Box S |
|
Purple marbles |
Black marbles |
Purple marbles |
Black marbles |
Before |
2 |
4 |
20 |
12 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
4 p |
1 p |
50% =
50100 = 12
80% =
80100 = 45
Number of purple marbles = 2 + 20 = 22
Number of black marbles = 4 + 12 = 16
1 u + 4 p = 22 --- (1)
1 u + 1 p = 16 ---(2)
(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 22 - 16
4 p - 1 p = 6
3 p = 6
1 p = 6 ÷ 3 = 2
From (2):
1 u + 1 p = 16
1 u + 1 x 2 = 16
1 u + 2 = 16
1 u = 16 - 2 = 14
Number of black marbles to be transferred from Box S to Box R
= 12 - 1 p
= 12 - 1 x 2
= 12 - 2
= 10
Number of purple marbles to be transferred from Box S to Box R
= 1 u - 2
= 14 - 2
= 12
Total number of black and purple marbles to be transferred from Box S to Box R
= 10 + 12
= 22
Answer(s): 22