Container G contains 9 blue balls and 12 green balls. Container H contains 14 blue balls and 5 green balls. How many green balls and blue balls must be transferred from Container H to put into Container G so that 50% of the balls in Container A are blue and 75% of the balls in Container H are blue?

	Container G		Container H
	Blue balls	Green balls	Blue balls	Green balls
Before	9	12	14	5
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of blue balls = 9 + 14 = 23 

Number of green balls = 12 + 5 = 17 

1 u + 3 p = 23 --- (1)

1 u + 1 p = 17 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 23 - 17
3 p - 1 p = 6
2 p = 6

1 p = 6 ÷ 2 = 3

From (2):
1 u + 1 p = 17
1 u + 1 x 3 = 17
1 u + 3 = 17

1 u = 17 - 3 = 14

Number of green balls to be transferred from Container H to Container G
= 5 - 1 p
= 5 - 1 x 3
= 5 - 3
= 2

Number of blue balls to be transferred from Container H to Container G
= 1 u - 9
= 14 - 9
= 5

Total number of green and blue balls to be transferred from Container H to Container G
= 2 + 5
= 7

Answer(s): 7