Crate H contains 5 green balls and 17 pink balls. Crate J contains 28 green balls and 8 pink balls. How many pink balls and green balls must be removed from Crate J to put into Crate H so that 50% of the balls in Crate A are green and 70% of the balls in Crate J are green?

	Crate H		Crate J
	Green balls	Pink balls	Green balls	Pink balls
Before	5	17	28	8
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	7 p	3 p

50% = ⁵⁰₁₀₀ = 12

70% = ⁷⁰₁₀₀ = 710

Number of green balls = 5 + 28 = 33 

Number of pink balls = 17 + 8 = 25 

1 u + 7 p = 33 --- (1)

1 u + 3 p = 25 ---(2)

(1) - (2)
(1 u + 7 p) - (1 u + 3 p) = 33 - 25
7 p - 3 p = 8
4 p = 8

1 p = 8 ÷ 4 = 2

From (2):
1 u + 3 p = 25
1 u + 3 x 2 = 25
1 u + 6 = 25

1 u = 25 - 6 = 19

Number of pink balls to be removed from Crate J to Crate H
= 8 - 3 p
= 8 - 3 x 2
= 8 - 6
= 2

Number of green balls to be removed from Crate J to Crate H
= 1 u - 5
= 19 - 5
= 14

Total number of pink and green balls to be removed from Crate J to Crate H
= 2 + 14
= 16

Answer(s): 16