Container H contains 2 white balls and 3 blue balls. Container J contains 86 white balls and 28 blue balls. How many blue balls and white balls must be moved from Container J to put into Container H so that 50% of the balls in Container A are white and 80% of the balls in Container J are white?

	Container H		Container J
	White balls	Blue balls	White balls	Blue balls
Before	2	3	86	28
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	4 p	1 p

50% = ⁵⁰₁₀₀ = 12

80% = ⁸⁰₁₀₀ = 45

Number of white balls = 2 + 86 = 88 

Number of blue balls = 3 + 28 = 31 

1 u + 4 p = 88 --- (1)

1 u + 1 p = 31 ---(2)

(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 88 - 31
4 p - 1 p = 57
3 p = 57

1 p = 57 ÷ 3 = 19

From (2):
1 u + 1 p = 31
1 u + 1 x 19 = 31
1 u + 19 = 31

1 u = 31 - 19 = 12

Number of blue balls to be moved from Container J to Container H
= 28 - 1 p
= 28 - 1 x 19
= 28 - 19
= 9

Number of white balls to be moved from Container J to Container H
= 1 u - 2
= 12 - 2
= 10

Total number of blue and white balls to be moved from Container J to Container H
= 9 + 10
= 19

Answer(s): 19