Box S contains 5 pink beads and 6 yellow beads. Box T contains 24 pink beads and 8 yellow beads. How many yellow beads and pink beads must be moved from Box T to put into Box S so that 50% of the beads in Box A are pink and 80% of the beads in Box T are pink?
|
Box S |
Box T |
|
Pink beads |
Yellow beads |
Pink beads |
Yellow beads |
Before |
5 |
6 |
24 |
8 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
4 p |
1 p |
50% =
50100 = 12
80% =
80100 = 45
Number of pink beads = 5 + 24 = 29
Number of yellow beads = 6 + 8 = 14
1 u + 4 p = 29 --- (1)
1 u + 1 p = 14 ---(2)
(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 29 - 14
4 p - 1 p = 15
3 p = 15
1 p = 15 ÷ 3 = 5
From (2):
1 u + 1 p = 14
1 u + 1 x 5 = 14
1 u + 5 = 14
1 u = 14 - 5 = 9
Number of yellow beads to be moved from Box T to Box S
= 8 - 1 p
= 8 - 1 x 5
= 8 - 5
= 3
Number of pink beads to be moved from Box T to Box S
= 1 u - 5
= 9 - 5
= 4
Total number of yellow and pink beads to be moved from Box T to Box S
= 3 + 4
= 7
Answer(s): 7