Box X contains 4 gold beads and 8 white beads. Box Y contains 59 gold beads and 19 white beads. How many white beads and gold beads must be moved from Box Y to put into Box X so that 50% of the beads in Box A are gold and 80% of the beads in Box Y are gold?
|
Box X |
Box Y |
|
Gold beads |
White beads |
Gold beads |
White beads |
Before |
4 |
8 |
59 |
19 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
4 p |
1 p |
50% =
50100 = 12
80% =
80100 = 45
Number of gold beads = 4 + 59 = 63
Number of white beads = 8 + 19 = 27
1 u + 4 p = 63 --- (1)
1 u + 1 p = 27 ---(2)
(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 63 - 27
4 p - 1 p = 36
3 p = 36
1 p = 36 ÷ 3 = 12
From (2):
1 u + 1 p = 27
1 u + 1 x 12 = 27
1 u + 12 = 27
1 u = 27 - 12 = 15
Number of white beads to be moved from Box Y to Box X
= 19 - 1 p
= 19 - 1 x 12
= 19 - 12
= 7
Number of gold beads to be moved from Box Y to Box X
= 1 u - 4
= 15 - 4
= 11
Total number of white and gold beads to be moved from Box Y to Box X
= 7 + 11
= 18
Answer(s): 18