Box S contains 9 brown marbles and 11 grey marbles. Box T contains 23 brown marbles and 11 grey marbles. How many grey marbles and brown marbles must be moved from Box T to put into Box S so that 50% of the marbles in Box A are brown and 75% of the marbles in Box T are brown?
|
Box S |
Box T |
|
Brown marbles |
Grey marbles |
Brown marbles |
Grey marbles |
Before |
9 |
11 |
23 |
11 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
3 p |
1 p |
50% =
50100 = 12
75% =
75100 = 34
Number of brown marbles = 9 + 23 = 32
Number of grey marbles = 11 + 11 = 22
1 u + 3 p = 32 --- (1)
1 u + 1 p = 22 ---(2)
(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 32 - 22
3 p - 1 p = 10
2 p = 10
1 p = 10 ÷ 2 = 5
From (2):
1 u + 1 p = 22
1 u + 1 x 5 = 22
1 u + 5 = 22
1 u = 22 - 5 = 17
Number of grey marbles to be moved from Box T to Box S
= 11 - 1 p
= 11 - 1 x 5
= 11 - 5
= 6
Number of brown marbles to be moved from Box T to Box S
= 1 u - 9
= 17 - 9
= 8
Total number of grey and brown marbles to be moved from Box T to Box S
= 6 + 8
= 14
Answer(s): 14