Crate G contains 12 green beads and 6 blue beads. Crate H contains 46 green beads and 24 blue beads. How many blue beads and green beads must be transferred from Crate H to put into Crate G so that 50% of the beads in Crate A are green and 75% of the beads in Crate H are green?

	Crate G		Crate H
	Green beads	Blue beads	Green beads	Blue beads
Before	12	6	46	24
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of green beads = 12 + 46 = 58 

Number of blue beads = 6 + 24 = 30 

1 u + 3 p = 58 --- (1)

1 u + 1 p = 30 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 58 - 30
3 p - 1 p = 28
2 p = 28

1 p = 28 ÷ 2 = 14

From (2):
1 u + 1 p = 30
1 u + 1 x 14 = 30
1 u + 14 = 30

1 u = 30 - 14 = 16

Number of blue beads to be transferred from Crate H to Crate G
= 24 - 1 p
= 24 - 1 x 14
= 24 - 14
= 10

Number of green beads to be transferred from Crate H to Crate G
= 1 u - 12
= 16 - 12
= 4

Total number of blue and green beads to be transferred from Crate H to Crate G
= 10 + 4
= 14

Answer(s): 14