Container H contains 2 pink balls and 7 red balls. Container J contains 95 pink balls and 46 red balls. How many red balls and pink balls must be moved from Container J to put into Container H so that 50% of the balls in Container A are pink and 70% of the balls in Container J are pink?

	Container H		Container J
	Pink balls	Red balls	Pink balls	Red balls
Before	2	7	95	46
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	7 p	3 p

50% = ⁵⁰₁₀₀ = 12

70% = ⁷⁰₁₀₀ = 710

Number of pink balls = 2 + 95 = 97 

Number of red balls = 7 + 46 = 53 

1 u + 7 p = 97 --- (1)

1 u + 3 p = 53 ---(2)

(1) - (2)
(1 u + 7 p) - (1 u + 3 p) = 97 - 53
7 p - 3 p = 44
4 p = 44

1 p = 44 ÷ 4 = 11

From (2):
1 u + 3 p = 53
1 u + 3 x 11 = 53
1 u + 33 = 53

1 u = 53 - 33 = 20

Number of red balls to be moved from Container J to Container H
= 46 - 3 p
= 46 - 3 x 11
= 46 - 33
= 13

Number of pink balls to be moved from Container J to Container H
= 1 u - 2
= 20 - 2
= 18

Total number of red and pink balls to be moved from Container J to Container H
= 13 + 18
= 31

Answer(s): 31