Container L contains 9 white marbles and 10 purple marbles. Container M contains 90 white marbles and 41 purple marbles. How many purple marbles and white marbles must be moved from Container M to put into Container L so that 50% of the marbles in Container A are white and 70% of the marbles in Container M are white?
|
Container L |
Container M |
|
White marbles |
Purple marbles |
White marbles |
Purple marbles |
Before |
9 |
10 |
90 |
41 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
7 p |
3 p |
50% =
50100 = 12
70% =
70100 = 710
Number of white marbles = 9 + 90 = 99
Number of purple marbles = 10 + 41 = 51
1 u + 7 p = 99 --- (1)
1 u + 3 p = 51 ---(2)
(1) - (2)
(1 u + 7 p) - (1 u + 3 p) = 99 - 51
7 p - 3 p = 48
4 p = 48
1 p = 48 ÷ 4 = 12
From (2):
1 u + 3 p = 51
1 u + 3 x 12 = 51
1 u + 36 = 51
1 u = 51 - 36 = 15
Number of purple marbles to be moved from Container M to Container L
= 41 - 3 p
= 41 - 3 x 12
= 41 - 36
= 5
Number of white marbles to be moved from Container M to Container L
= 1 u - 9
= 15 - 9
= 6
Total number of purple and white marbles to be moved from Container M to Container L
= 5 + 6
= 11
Answer(s): 11