Box G contains 3 brown beads and 2 blue beads. Box H contains 65 brown beads and 27 blue beads. How many blue beads and brown beads must be removed from Box H to put into Box G so that 50% of the beads in Box A are brown and 80% of the beads in Box H are brown?

	Box G		Box H
	Brown beads	Blue beads	Brown beads	Blue beads
Before	3	2	65	27
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	4 p	1 p

50% = ⁵⁰₁₀₀ = 12

80% = ⁸⁰₁₀₀ = 45

Number of brown beads = 3 + 65 = 68 

Number of blue beads = 2 + 27 = 29 

1 u + 4 p = 68 --- (1)

1 u + 1 p = 29 ---(2)

(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 68 - 29
4 p - 1 p = 39
3 p = 39

1 p = 39 ÷ 3 = 13

From (2):
1 u + 1 p = 29
1 u + 1 x 13 = 29
1 u + 13 = 29

1 u = 29 - 13 = 16

Number of blue beads to be removed from Box H to Box G
= 27 - 1 p
= 27 - 1 x 13
= 27 - 13
= 14

Number of brown beads to be removed from Box H to Box G
= 1 u - 3
= 16 - 3
= 13

Total number of blue and brown beads to be removed from Box H to Box G
= 14 + 13
= 27

Answer(s): 27