Container W contains 10 black marbles and 11 blue marbles. Container X contains 40 black marbles and 15 blue marbles. How many blue marbles and black marbles must be transferred from Container X to put into Container W so that 50% of the marbles in Container A are black and 75% of the marbles in Container X are black?
|
Container W |
Container X |
|
Black marbles |
Blue marbles |
Black marbles |
Blue marbles |
Before |
10 |
11 |
40 |
15 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
3 p |
1 p |
50% =
50100 = 12
75% =
75100 = 34
Number of black marbles = 10 + 40 = 50
Number of blue marbles = 11 + 15 = 26
1 u + 3 p = 50 --- (1)
1 u + 1 p = 26 ---(2)
(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 50 - 26
3 p - 1 p = 24
2 p = 24
1 p = 24 ÷ 2 = 12
From (2):
1 u + 1 p = 26
1 u + 1 x 12 = 26
1 u + 12 = 26
1 u = 26 - 12 = 14
Number of blue marbles to be transferred from Container X to Container W
= 15 - 1 p
= 15 - 1 x 12
= 15 - 12
= 3
Number of black marbles to be transferred from Container X to Container W
= 1 u - 10
= 14 - 10
= 4
Total number of blue and black marbles to be transferred from Container X to Container W
= 3 + 4
= 7
Answer(s): 7