There were some brown beads and green beads. The beads were packed into 2 bags. At first, Bag A contained 230 beads and 30% of them were green beads. Bag B contained 540 beads and 60% of them were green beads. How many brown beads and green beads in total must be moved from Bag A to Bag B such that 25% of the beads in Bag A are brown and 50% of the beads in Bag B are green?

	Bag A		Bag B
Total	230		540
	Green beads	Brown beads	Green beads	Brown beads
Before	69	161	324	216
Change	- ?	- ?	+ ?	+ ?
After	3 u	1 u	1 p	1 p

Number of green beads in Bag A at first
= 30% x 230
= ³⁰₁₀₀ x 230
= 69

Number of brown beads in Bag A at first
= 230 - 69
= 161

Number of green beads in Bag B at first
= 60% x 540
= ⁶⁰₁₀₀ x 540
= 324

Number of brown beads in Bag B at first
= 540 - 324
= 216

Bag A in the end
25% = ²⁵₁₀₀ =¹₄
Green beads : Brown beads = 3 : 1

Bag B in the end
50% = ⁵⁰₁₀₀ =¹₂
Green beads : Brown beads = 1 : 1

Total number of green beads = 3 u + 1 p

3 u + 1 p = 69 + 324
3 u + 1 p = 393 

1 p = 393 - 3 u --- (1)

Total number of brown beads = 1 u + 1 p
1 u + 1 p = 161 + 216
1 u + 1 p = 377

1 p = 377 - 1 u --- (2)

(2) = (1)
377 - 1 u = 393 - 3 u
3 u - 1 u = 393 - 377
2 u = 16

1 u = 16 ÷ 2 = 8

Total number of brown beads and green beads that must be moved from Bag A to Bag B
= 230 - 4 u
= 230 - 4 x 8
= 230 - 32
= 198

Answer(s): 198