There were some silver stickers and blue stickers. The stickers were packed into 2 bags. At first, Bag V contained 75 stickers and 40% of them were blue stickers. Bag W contained 155 stickers and 60% of them were blue stickers. How many silver stickers and blue stickers in total must be moved from Bag V to Bag W such that 30% of the stickers in Bag V are silver and 50% of the stickers in Bag W are blue?

	Bag V		Bag W
Total	75		155
	Blue stickers	Silver stickers	Blue stickers	Silver stickers
Before	30	45	93	62
Change	- ?	- ?	+ ?	+ ?
After	7 u	3 u	1 p	1 p

Number of blue stickers in Bag V at first
= 40% x 75
= ⁴⁰₁₀₀ x 75
= 30

Number of silver stickers in Bag V at first
= 75 - 30
= 45

Number of blue stickers in Bag W at first
= 60% x 155
= ⁶⁰₁₀₀ x 155
= 93

Number of silver stickers in Bag W at first
= 155 - 93
= 62

Bag V in the end
30% = ³⁰₁₀₀ =³₁₀
Blue stickers : Silver stickers = 7 : 3

Bag W in the end
50% = ⁵⁰₁₀₀ =¹₂
Blue stickers : Silver stickers = 1 : 1

Total number of blue stickers = 7 u + 1 p

7 u + 1 p = 30 + 93
7 u + 1 p = 123 

1 p = 123 - 7 u --- (1)

Total number of silver stickers = 3 u + 1 p
3 u + 1 p = 45 + 62
3 u + 1 p = 107

1 p = 107 - 3 u --- (2)

(2) = (1)
107 - 3 u = 123 - 7 u
7 u - 3 u = 123 - 107
4 u = 16

1 u = 16 ÷ 4 = 4

Total number of silver stickers and blue stickers that must be moved from Bag V to Bag W
= 75 - 10 u
= 75 - 10 x 4
= 75 - 40
= 35

Answer(s): 35