There were some yellow stickers and blue stickers. The stickers were packed into 2 bags. At first, Box X contained 140 stickers and 40% of them were blue stickers. Box Y contained 160 stickers and 60% of them were blue stickers. How many yellow stickers and blue stickers in total must be moved from Box X to Box Y such that 25% of the stickers in Box X are yellow and 50% of the stickers in Box Y are blue?

	Box X		Box Y
Total	140		160
	Blue stickers	Yellow stickers	Blue stickers	Yellow stickers
Before	56	84	96	64
Change	- ?	- ?	+ ?	+ ?
After	3 u	1 u	1 p	1 p

Number of blue stickers in Box X at first
= 40% x 140
= ⁴⁰₁₀₀ x 140
= 56

Number of yellow stickers in Box X at first
= 140 - 56
= 84

Number of blue stickers in Box Y at first
= 60% x 160
= ⁶⁰₁₀₀ x 160
= 96

Number of yellow stickers in Box Y at first
= 160 - 96
= 64

Box X in the end
25% = ²⁵₁₀₀ =¹₄
Blue stickers : Yellow stickers = 3 : 1

Box Y in the end
50% = ⁵⁰₁₀₀ =¹₂
Blue stickers : Yellow stickers = 1 : 1

Total number of blue stickers = 3 u + 1 p

3 u + 1 p = 56 + 96
3 u + 1 p = 152 

1 p = 152 - 3 u --- (1)

Total number of yellow stickers = 1 u + 1 p
1 u + 1 p = 84 + 64
1 u + 1 p = 148

1 p = 148 - 1 u --- (2)

(2) = (1)
148 - 1 u = 152 - 3 u
3 u - 1 u = 152 - 148
2 u = 4

1 u = 4 ÷ 2 = 2

Total number of yellow stickers and blue stickers that must be moved from Box X to Box Y
= 140 - 4 u
= 140 - 4 x 2
= 140 - 8
= 132

Answer(s): 132