There were some brown buttons and pink buttons. The buttons were packed into 2 bags. At first, Bag H contained 80 buttons and 40% of them were pink buttons. Bag J contained 44 buttons and 75% of them were pink buttons. How many brown buttons and pink buttons in total must be moved from Bag H to Bag J such that 25% of the buttons in Bag H are brown and 50% of the buttons in Bag J are pink?
|
Bag H |
Bag J |
Total |
80 |
44 |
|
Pink buttons |
Brown buttons |
Pink buttons |
Brown buttons |
Before |
32 |
48 |
33 |
11 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
3 u |
1 u |
1 p |
1 p |
Number of pink buttons in Bag H at first
= 40% x 80
=
40100 x 80
= 32
Number of brown buttons in Bag H at first
= 80 - 32
= 48
Number of pink buttons in Bag J at first
= 75% x 44
=
75100 x 44
= 33
Number of brown buttons in Bag J at first
= 44 - 33
= 11
Bag H in the end25% =
25100 =
14 Pink buttons : Brown buttons = 3 : 1
Bag J in the end50% =
50100 =
12Pink buttons : Brown buttons = 1 : 1
Total number of pink buttons = 3 u + 1 p
3 u + 1 p = 32 + 33
3 u + 1 p = 65
1 p = 65 - 3 u --- (1)
Total number of brown buttons = 1 u + 1 p
1 u + 1 p = 48 + 11
1 u + 1 p = 59
1 p = 59 - 1 u --- (2)
(2) = (1)
59 - 1 u = 65 - 3 u
3 u - 1 u = 65 - 59
2 u = 6
1 u = 6 ÷ 2 = 3
Total number of brown buttons and pink buttons that must be moved from Bag H to Bag J
= 80 - 4 u
= 80 - 4 x 3
= 80 - 12
= 68
Answer(s): 68