There were some red stamps and yellow stamps. The stamps were packed into 2 bags. At first, Box C contained 135 stamps and 40% of them were yellow stamps. Box D contained 55 stamps and 80% of them were yellow stamps. How many red stamps and yellow stamps in total must be moved from Box C to Box D such that 20% of the stamps in Box C are red and 50% of the stamps in Box D are yellow?
|
Box C |
Box D |
Total |
135 |
55 |
|
Yellow stamps |
Red stamps |
Yellow stamps |
Red stamps |
Before |
54 |
81 |
44 |
11 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
4 u |
1 u |
1 p |
1 p |
Number of yellow stamps in Box C at first
= 40% x 135
=
40100 x 135
= 54
Number of red stamps in Box C at first
= 135 - 54
= 81
Number of yellow stamps in Box D at first
= 80% x 55
=
80100 x 55
= 44
Number of red stamps in Box D at first
= 55 - 44
= 11
Box C in the end20% =
20100 =
15 Yellow stamps : Red stamps = 4 : 1
Box D in the end50% =
50100 =
12Yellow stamps : Red stamps = 1 : 1
Total number of yellow stamps = 4 u + 1 p
4 u + 1 p = 54 + 44
4 u + 1 p = 98
1 p = 98 - 4 u --- (1)
Total number of red stamps = 1 u + 1 p
1 u + 1 p = 81 + 11
1 u + 1 p = 92
1 p = 92 - 1 u --- (2)
(2) = (1)
92 - 1 u = 98 - 4 u
4 u - 1 u = 98 - 92
3 u = 6
1 u = 6 ÷ 3 = 2
Total number of red stamps and yellow stamps that must be moved from Box C to Box D
= 135 - 5 u
= 135 - 5 x 2
= 135 - 10
= 125
Answer(s): 125