There were some silver stickers and pink stickers. The stickers were packed into 2 bags. At first, Packet A contained 180 stickers and 30% of them were pink stickers. Packet B contained 165 stickers and 80% of them were pink stickers. How many silver stickers and pink stickers in total must be moved from Packet A to Packet B such that 20% of the stickers in Packet A are silver and 50% of the stickers in Packet B are pink?

	Packet A		Packet B
Total	180		165
	Pink stickers	Silver stickers	Pink stickers	Silver stickers
Before	54	126	132	33
Change	- ?	- ?	+ ?	+ ?
After	4 u	1 u	1 p	1 p

Number of pink stickers in Packet A at first
= 30% x 180
= ³⁰₁₀₀ x 180
= 54

Number of silver stickers in Packet A at first
= 180 - 54
= 126

Number of pink stickers in Packet B at first
= 80% x 165
= ⁸⁰₁₀₀ x 165
= 132

Number of silver stickers in Packet B at first
= 165 - 132
= 33

Packet A in the end
20% = ²⁰₁₀₀ =¹₅
Pink stickers : Silver stickers = 4 : 1

Packet B in the end
50% = ⁵⁰₁₀₀ =¹₂
Pink stickers : Silver stickers = 1 : 1

Total number of pink stickers = 4 u + 1 p

4 u + 1 p = 54 + 132
4 u + 1 p = 186 

1 p = 186 - 4 u --- (1)

Total number of silver stickers = 1 u + 1 p
1 u + 1 p = 126 + 33
1 u + 1 p = 159

1 p = 159 - 1 u --- (2)

(2) = (1)
159 - 1 u = 186 - 4 u
4 u - 1 u = 186 - 159
3 u = 27

1 u = 27 ÷ 3 = 9

Total number of silver stickers and pink stickers that must be moved from Packet A to Packet B
= 180 - 5 u
= 180 - 5 x 9
= 180 - 45
= 135

Answer(s): 135