There were some grey beads and green beads. The beads were packed into 2 bags. At first, Box P contained 190 beads and 10% of them were green beads. Box Q contained 324 beads and 75% of them were green beads. How many grey beads and green beads in total must be moved from Box P to Box Q such that 25% of the beads in Box P are grey and 50% of the beads in Box Q are green?
|
Box P |
Box Q |
Total |
190 |
324 |
|
Green beads |
Grey beads |
Green beads |
Grey beads |
Before |
19 |
171 |
243 |
81 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
3 u |
1 u |
1 p |
1 p |
Number of green beads in Box P at first
= 10% x 190
=
10100 x 190
= 19
Number of grey beads in Box P at first
= 190 - 19
= 171
Number of green beads in Box Q at first
= 75% x 324
=
75100 x 324
= 243
Number of grey beads in Box Q at first
= 324 - 243
= 81
Box P in the end25% =
25100 =
14 Green beads : Grey beads = 3 : 1
Box Q in the end50% =
50100 =
12Green beads : Grey beads = 1 : 1
Total number of green beads = 3 u + 1 p
3 u + 1 p = 19 + 243
3 u + 1 p = 262
1 p = 262 - 3 u --- (1)
Total number of grey beads = 1 u + 1 p
1 u + 1 p = 171 + 81
1 u + 1 p = 252
1 p = 252 - 1 u --- (2)
(2) = (1)
252 - 1 u = 262 - 3 u
3 u - 1 u = 262 - 252
2 u = 10
1 u = 10 ÷ 2 = 5
Total number of grey beads and green beads that must be moved from Box P to Box Q
= 190 - 4 u
= 190 - 4 x 5
= 190 - 20
= 170
Answer(s): 170