There were some purple pens and yellow pens. The pens were packed into 2 bags. At first, Bag P contained 260 pens and 10% of them were yellow pens. Bag Q contained 444 pens and 75% of them were yellow pens. How many purple pens and yellow pens in total must be moved from Bag P to Bag Q such that 25% of the pens in Bag P are purple and 50% of the pens in Bag Q are yellow?
|
Bag P |
Bag Q |
Total |
260 |
444 |
|
Yellow pens |
Purple pens |
Yellow pens |
Purple pens |
Before |
26 |
234 |
333 |
111 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
3 u |
1 u |
1 p |
1 p |
Number of yellow pens in Bag P at first
= 10% x 260
=
10100 x 260
= 26
Number of purple pens in Bag P at first
= 260 - 26
= 234
Number of yellow pens in Bag Q at first
= 75% x 444
=
75100 x 444
= 333
Number of purple pens in Bag Q at first
= 444 - 333
= 111
Bag P in the end25% =
25100 =
14 Yellow pens : Purple pens = 3 : 1
Bag Q in the end50% =
50100 =
12Yellow pens : Purple pens = 1 : 1
Total number of yellow pens = 3 u + 1 p
3 u + 1 p = 26 + 333
3 u + 1 p = 359
1 p = 359 - 3 u --- (1)
Total number of purple pens = 1 u + 1 p
1 u + 1 p = 234 + 111
1 u + 1 p = 345
1 p = 345 - 1 u --- (2)
(2) = (1)
345 - 1 u = 359 - 3 u
3 u - 1 u = 359 - 345
2 u = 14
1 u = 14 ÷ 2 = 7
Total number of purple pens and yellow pens that must be moved from Bag P to Bag Q
= 260 - 4 u
= 260 - 4 x 7
= 260 - 28
= 232
Answer(s): 232