There were some brown beads and gold beads. The beads were packed into 2 bags. At first, Bag H contained 150 beads and 30% of them were gold beads. Bag J contained 430 beads and 60% of them were gold beads. How many brown beads and gold beads in total must be moved from Bag H to Bag J such that 25% of the beads in Bag H are brown and 50% of the beads in Bag J are gold?
|
Bag H |
Bag J |
Total |
150 |
430 |
|
Gold beads |
Brown beads |
Gold beads |
Brown beads |
Before |
45 |
105 |
258 |
172 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
3 u |
1 u |
1 p |
1 p |
Number of gold beads in Bag H at first
= 30% x 150
=
30100 x 150
= 45
Number of brown beads in Bag H at first
= 150 - 45
= 105
Number of gold beads in Bag J at first
= 60% x 430
=
60100 x 430
= 258
Number of brown beads in Bag J at first
= 430 - 258
= 172
Bag H in the end25% =
25100 =
14 Gold beads : Brown beads = 3 : 1
Bag J in the end50% =
50100 =
12Gold beads : Brown beads = 1 : 1
Total number of gold beads = 3 u + 1 p
3 u + 1 p = 45 + 258
3 u + 1 p = 303
1 p = 303 - 3 u --- (1)
Total number of brown beads = 1 u + 1 p
1 u + 1 p = 105 + 172
1 u + 1 p = 277
1 p = 277 - 1 u --- (2)
(2) = (1)
277 - 1 u = 303 - 3 u
3 u - 1 u = 303 - 277
2 u = 26
1 u = 26 ÷ 2 = 13
Total number of brown beads and gold beads that must be moved from Bag H to Bag J
= 150 - 4 u
= 150 - 4 x 13
= 150 - 52
= 98
Answer(s): 98