There were some pink stickers and silver stickers. The stickers were packed into 2 bags. At first, Packet X contained 140 stickers and 40% of them were silver stickers. Packet Y contained 80 stickers and 75% of them were silver stickers. How many pink stickers and silver stickers in total must be moved from Packet X to Packet Y such that 30% of the stickers in Packet X are pink and 50% of the stickers in Packet Y are silver?

	Packet X		Packet Y
Total	140		80
	Silver stickers	Pink stickers	Silver stickers	Pink stickers
Before	56	84	60	20
Change	- ?	- ?	+ ?	+ ?
After	7 u	3 u	1 p	1 p

Number of silver stickers in Packet X at first
= 40% x 140
= ⁴⁰₁₀₀ x 140
= 56

Number of pink stickers in Packet X at first
= 140 - 56
= 84

Number of silver stickers in Packet Y at first
= 75% x 80
= ⁷⁵₁₀₀ x 80
= 60

Number of pink stickers in Packet Y at first
= 80 - 60
= 20

Packet X in the end
30% = ³⁰₁₀₀ =³₁₀
Silver stickers : Pink stickers = 7 : 3

Packet Y in the end
50% = ⁵⁰₁₀₀ =¹₂
Silver stickers : Pink stickers = 1 : 1

Total number of silver stickers = 7 u + 1 p

7 u + 1 p = 56 + 60
7 u + 1 p = 116 

1 p = 116 - 7 u --- (1)

Total number of pink stickers = 3 u + 1 p
3 u + 1 p = 84 + 20
3 u + 1 p = 104

1 p = 104 - 3 u --- (2)

(2) = (1)
104 - 3 u = 116 - 7 u
7 u - 3 u = 116 - 104
4 u = 12

1 u = 12 ÷ 4 = 3

Total number of pink stickers and silver stickers that must be moved from Packet X to Packet Y
= 140 - 10 u
= 140 - 10 x 3
= 140 - 30
= 110

Answer(s): 110