There were some pink stickers and blue stickers. The stickers were packed into 2 bags. At first, Box L contained 90 stickers and 40% of them were blue stickers. Box M contained 68 stickers and 75% of them were blue stickers. How many pink stickers and blue stickers in total must be moved from Box L to Box M such that 25% of the stickers in Box L are pink and 50% of the stickers in Box M are blue?
|
Box L |
Box M |
Total |
90 |
68 |
|
Blue stickers |
Pink stickers |
Blue stickers |
Pink stickers |
Before |
36 |
54 |
51 |
17 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
3 u |
1 u |
1 p |
1 p |
Number of blue stickers in Box L at first
= 40% x 90
=
40100 x 90
= 36
Number of pink stickers in Box L at first
= 90 - 36
= 54
Number of blue stickers in Box M at first
= 75% x 68
=
75100 x 68
= 51
Number of pink stickers in Box M at first
= 68 - 51
= 17
Box L in the end25% =
25100 =
14 Blue stickers : Pink stickers = 3 : 1
Box M in the end50% =
50100 =
12Blue stickers : Pink stickers = 1 : 1
Total number of blue stickers = 3 u + 1 p
3 u + 1 p = 36 + 51
3 u + 1 p = 87
1 p = 87 - 3 u --- (1)
Total number of pink stickers = 1 u + 1 p
1 u + 1 p = 54 + 17
1 u + 1 p = 71
1 p = 71 - 1 u --- (2)
(2) = (1)
71 - 1 u = 87 - 3 u
3 u - 1 u = 87 - 71
2 u = 16
1 u = 16 ÷ 2 = 8
Total number of pink stickers and blue stickers that must be moved from Box L to Box M
= 90 - 4 u
= 90 - 4 x 8
= 90 - 32
= 58
Answer(s): 58