There were some brown stamps and pink stamps. The stamps were packed into 2 bags. At first, Packet T contained 150 stamps and 10% of them were pink stamps. Packet U contained 640 stamps and 60% of them were pink stamps. How many brown stamps and pink stamps in total must be moved from Packet T to Packet U such that 25% of the stamps in Packet T are brown and 50% of the stamps in Packet U are pink?
|
Packet T |
Packet U |
Total |
150 |
640 |
|
Pink stamps |
Brown stamps |
Pink stamps |
Brown stamps |
Before |
15 |
135 |
384 |
256 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
3 u |
1 u |
1 p |
1 p |
Number of pink stamps in Packet T at first
= 10% x 150
=
10100 x 150
= 15
Number of brown stamps in Packet T at first
= 150 - 15
= 135
Number of pink stamps in Packet U at first
= 60% x 640
=
60100 x 640
= 384
Number of brown stamps in Packet U at first
= 640 - 384
= 256
Packet T in the end25% =
25100 =
14 Pink stamps : Brown stamps = 3 : 1
Packet U in the end50% =
50100 =
12Pink stamps : Brown stamps = 1 : 1
Total number of pink stamps = 3 u + 1 p
3 u + 1 p = 15 + 384
3 u + 1 p = 399
1 p = 399 - 3 u --- (1)
Total number of brown stamps = 1 u + 1 p
1 u + 1 p = 135 + 256
1 u + 1 p = 391
1 p = 391 - 1 u --- (2)
(2) = (1)
391 - 1 u = 399 - 3 u
3 u - 1 u = 399 - 391
2 u = 8
1 u = 8 ÷ 2 = 4
Total number of brown stamps and pink stamps that must be moved from Packet T to Packet U
= 150 - 4 u
= 150 - 4 x 4
= 150 - 16
= 134
Answer(s): 134