There were some red buttons and silver buttons. The buttons were packed into 2 bags. At first, Box T contained 280 buttons and 30% of them were silver buttons. Box U contained 780 buttons and 60% of them were silver buttons. How many red buttons and silver buttons in total must be moved from Box T to Box U such that 30% of the buttons in Box T are red and 50% of the buttons in Box U are silver?
|
Box T |
Box U |
Total |
280 |
780 |
|
Silver buttons |
Red buttons |
Silver buttons |
Red buttons |
Before |
84 |
196 |
468 |
312 |
Change |
- ? |
- ? |
+ ? |
+ ? |
After |
7 u |
3 u |
1 p |
1 p |
Number of silver buttons in Box T at first
= 30% x 280
=
30100 x 280
= 84
Number of red buttons in Box T at first
= 280 - 84
= 196
Number of silver buttons in Box U at first
= 60% x 780
=
60100 x 780
= 468
Number of red buttons in Box U at first
= 780 - 468
= 312
Box T in the end30% =
30100 =
310 Silver buttons : Red buttons = 7 : 3
Box U in the end50% =
50100 =
12Silver buttons : Red buttons = 1 : 1
Total number of silver buttons = 7 u + 1 p
7 u + 1 p = 84 + 468
7 u + 1 p = 552
1 p = 552 - 7 u --- (1)
Total number of red buttons = 3 u + 1 p
3 u + 1 p = 196 + 312
3 u + 1 p = 508
1 p = 508 - 3 u --- (2)
(2) = (1)
508 - 3 u = 552 - 7 u
7 u - 3 u = 552 - 508
4 u = 44
1 u = 44 ÷ 4 = 11
Total number of red buttons and silver buttons that must be moved from Box T to Box U
= 280 - 10 u
= 280 - 10 x 11
= 280 - 110
= 170
Answer(s): 170