At a party,
25 of the people are children. The remaining group of people is divided into men and women in the ratio of 2 : 7. Each man is given 4 chocolates and each woman is given 7 chocolates. Each accompanying child receives 8 chocolates. Given that only 582 chocolates are given away to women and children, how many less men are there than women?
Men |
Women |
Children |
3x3 |
2x3 |
2x1 |
7x1 |
|
2 u |
7 u |
6 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 9 is 9.
|
Men |
Women |
Children |
Number |
2 u |
7 u |
6 u |
Value |
4 |
7 |
8 |
Total value |
8 u |
49 u |
48 u |
Number of chocolates given away to women and children
= 49 u + 48 u
= 97 u
1 u = 582 ÷ 97 = 6
Number of less men than women
= 7 u - 2 u
= 5 u
= 5 x 6
= 30
Answer(s): 30