At a gathering,
14 of the people are children. The remaining group of people is divided into women and men in the ratio of 5 : 7. Each woman is given 2 candies and each man is given 4 candies. Each accompanying child receives 5 candies. Given that only 150 candies are given away to women and children, how many more adults are there than children?
| Women |
Men |
Children |
| 3x4 |
1x4 |
| 5x1 |
7x1 |
|
| 5 u |
7 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 12 is 12.
| |
Women |
Men |
Children |
| Number |
5 u |
7 u |
4 u |
| Value |
2 |
4 |
5 |
| Total value |
10 u |
28 u |
20 u |
Number of candies given away to women and children
= 10 u + 20 u
= 30 u
1 u = 150 ÷ 30 = 5
Number of adults
= 5 u + 7 u
= 12 u
Number of more adults than children
= 12 u - 4 u
= 8 u
= 8 x 5
= 40
Answer(s): 40
