At a gathering,
14 of the people are children. The remaining group of people is divided into women and men in the ratio of 4 : 7. Each woman is given 3 candies and each man is given 4 candies. Each accompanying child receives 5 candies. Given that only 546 candies are given away to women and children, how many more adults are there than children?
Women |
Men |
Children |
3x11 |
1x11 |
4x3 |
7x3 |
|
12 u |
21 u |
11 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 11 is 33.
|
Women |
Men |
Children |
Number |
12 u |
21 u |
11 u |
Value |
3 |
4 |
5 |
Total value |
36 u |
84 u |
55 u |
Number of candies given away to women and children
= 36 u + 55 u
= 91 u
1 u = 546 ÷ 91 = 6
Number of adults
= 12 u + 21 u
= 33 u
Number of more adults than children
= 33 u - 11 u
= 22 u
= 22 x 6
= 132
Answer(s): 132