At a gathering,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 5. Each man is given 3 candies and each woman is given 4 candies. Each accompanying child receives 5 candies. Given that only 400 candies are given away to women and children, how many less men are there than women?
Men |
Women |
Children |
2x4 |
1x4 |
3x1 |
5x1 |
|
3 u |
5 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 8 is 8.
|
Men |
Women |
Children |
Number |
3 u |
5 u |
4 u |
Value |
3 |
4 |
5 |
Total value |
9 u |
20 u |
20 u |
Number of candies given away to women and children
= 20 u + 20 u
= 40 u
1 u = 400 ÷ 40 = 10
Number of less men than women
= 5 u - 3 u
= 2 u
= 2 x 10
= 20
Answer(s): 20