At a party,
13 of the people are children. The remaining group of people is divided into women and men in the ratio of 2 : 3. Each woman is given 4 chocolates and each man is given 7 chocolates. Each accompanying child receives 8 chocolates. Given that only 410 chocolates are given away to men and children, how many less women are there than men?
Women |
Men |
Children |
2x5 |
1x5 |
2x2 |
3x2 |
|
4 u |
6 u |
5 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 5 is 10.
|
Women |
Men |
Children |
Number |
4 u |
6 u |
5 u |
Value |
4 |
7 |
8 |
Total value |
16 u |
42 u |
40 u |
Number of chocolates given away to men and children
= 42 u + 40 u
= 82 u
1 u = 410 ÷ 82 = 5
Number of less women than men
= 6 u - 4 u
= 2 u
= 2 x 5
= 10
Answer(s): 10