At a gathering,
13 of the people are children. The remaining group of people is divided into women and men in the ratio of 3 : 7. Each woman is given 3 sweets and each man is given 4 sweets. Each accompanying child receives 6 sweets. Given that only 156 sweets are given away to women and children, how many more adults are there than children?
| Women |
Men |
Children |
| 2x5 |
1x5 |
| 3x1 |
7x1 |
|
| 3 u |
7 u |
5 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 10 is 10.
| |
Women |
Men |
Children |
| Number |
3 u |
7 u |
5 u |
| Value |
3 |
4 |
6 |
| Total value |
9 u |
28 u |
30 u |
Number of sweets given away to women and children
= 9 u + 30 u
= 39 u
1 u = 156 ÷ 39 = 4
Number of adults
= 3 u + 7 u
= 10 u
Number of more adults than children
= 10 u - 5 u
= 5 u
= 5 x 4
= 20
Answer(s): 20
