At a party,
13 of the people are children. The remaining group of people is divided into women and men in the ratio of 3 : 7. Each woman is given 2 chocolates and each man is given 5 chocolates. Each accompanying child receives 7 chocolates. Given that only 82 chocolates are given away to women and children, how many more adults are there than children?
Women |
Men |
Children |
2x5 |
1x5 |
3x1 |
7x1 |
|
3 u |
7 u |
5 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 10 is 10.
|
Women |
Men |
Children |
Number |
3 u |
7 u |
5 u |
Value |
2 |
5 |
7 |
Total value |
6 u |
35 u |
35 u |
Number of chocolates given away to women and children
= 6 u + 35 u
= 41 u
1 u = 82 ÷ 41 = 2
Number of adults
= 3 u + 7 u
= 10 u
Number of more adults than children
= 10 u - 5 u
= 5 u
= 5 x 2
= 10
Answer(s): 10