At a gathering,
14 of the people are children. The remaining group of people is divided into men and women in the ratio of 5 : 7. Each man is given 3 sweets and each woman is given 4 sweets. Each accompanying child receives 7 sweets. Given that only 516 sweets are given away to men and children, how many more adults are there than children?
| Men |
Women |
Children |
| 3x4 |
1x4 |
| 5x1 |
7x1 |
|
| 5 u |
7 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 12 is 12.
| |
Men |
Women |
Children |
| Number |
5 u |
7 u |
4 u |
| Value |
3 |
4 |
7 |
| Total value |
15 u |
28 u |
28 u |
Number of sweets given away to men and children
= 15 u + 28 u
= 43 u
1 u = 516 ÷ 43 = 12
Number of adults
= 5 u + 7 u
= 12 u
Number of more adults than children
= 12 u - 4 u
= 8 u
= 8 x 12
= 96
Answer(s): 96
