At a gathering,
14 of the people are children. The remaining group of people is divided into men and women in the ratio of 5 : 7. Each man is given 2 sweets and each woman is given 5 sweets. Each accompanying child receives 8 sweets. Given that only 268 sweets are given away to women and children, how many less men are there than women?
| Men |
Women |
Children |
| 3x4 |
1x4 |
| 5x1 |
7x1 |
|
| 5 u |
7 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 12 is 12.
| |
Men |
Women |
Children |
| Number |
5 u |
7 u |
4 u |
| Value |
2 |
5 |
8 |
| Total value |
10 u |
35 u |
32 u |
Number of sweets given away to women and children
= 35 u + 32 u
= 67 u
1 u = 268 ÷ 67 = 4
Number of less men than women
= 7 u - 5 u
= 2 u
= 2 x 4
= 8
Answer(s): 8
