At a gathering,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 5. Each man is given 2 candies and each woman is given 5 candies. Each accompanying child receives 8 candies. Given that only 513 candies are given away to women and children, how many less men are there than women?
| Men |
Women |
Children |
| 2x4 |
1x4 |
| 3x1 |
5x1 |
|
| 3 u |
5 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 8 is 8.
| |
Men |
Women |
Children |
| Number |
3 u |
5 u |
4 u |
| Value |
2 |
5 |
8 |
| Total value |
6 u |
25 u |
32 u |
Number of candies given away to women and children
= 25 u + 32 u
= 57 u
1 u = 513 ÷ 57 = 9
Number of less men than women
= 5 u - 3 u
= 2 u
= 2 x 9
= 18
Answer(s): 18
