At a gathering,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 7. Each man is given 4 sweets and each woman is given 5 sweets. Each accompanying child receives 7 sweets. Given that only 560 sweets are given away to women and children, how many less men are there than women?
Men |
Women |
Children |
2x5 |
1x5 |
3x1 |
7x1 |
|
3 u |
7 u |
5 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 10 is 10.
|
Men |
Women |
Children |
Number |
3 u |
7 u |
5 u |
Value |
4 |
5 |
7 |
Total value |
12 u |
35 u |
35 u |
Number of sweets given away to women and children
= 35 u + 35 u
= 70 u
1 u = 560 ÷ 70 = 8
Number of less men than women
= 7 u - 3 u
= 4 u
= 4 x 8
= 32
Answer(s): 32