At a gathering,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 7. Each man is given 2 candies and each woman is given 3 candies. Each accompanying child receives 6 candies. Given that only 108 candies are given away to men and children, how many more adults are there than children?
| Men |
Women |
Children |
| 2x5 |
1x5 |
| 3x1 |
7x1 |
|
| 3 u |
7 u |
5 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 10 is 10.
| |
Men |
Women |
Children |
| Number |
3 u |
7 u |
5 u |
| Value |
2 |
3 |
6 |
| Total value |
6 u |
21 u |
30 u |
Number of candies given away to men and children
= 6 u + 30 u
= 36 u
1 u = 108 ÷ 36 = 3
Number of adults
= 3 u + 7 u
= 10 u
Number of more adults than children
= 10 u - 5 u
= 5 u
= 5 x 3
= 15
Answer(s): 15
