At a gathering,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 2 : 5. Each man is given 3 sweets and each woman is given 5 sweets. Each accompanying child receives 7 sweets. Given that only 549 sweets are given away to men and children, how many more adults are there than children?
Men |
Women |
Children |
2x7 |
1x7 |
2x2 |
5x2 |
|
4 u |
10 u |
7 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 7 is 14.
|
Men |
Women |
Children |
Number |
4 u |
10 u |
7 u |
Value |
3 |
5 |
7 |
Total value |
12 u |
50 u |
49 u |
Number of sweets given away to men and children
= 12 u + 49 u
= 61 u
1 u = 549 ÷ 61 = 9
Number of adults
= 4 u + 10 u
= 14 u
Number of more adults than children
= 14 u - 7 u
= 7 u
= 7 x 9
= 63
Answer(s): 63