At a party,
13 of the people are children. The remaining group of people is divided into women and men in the ratio of 2 : 7. Each woman is given 4 chocolates and each man is given 7 chocolates. Each accompanying child receives 10 chocolates. Given that only 530 chocolates are given away to women and children, how many more adults are there than children?
| Women |
Men |
Children |
| 2x9 |
1x9 |
| 2x2 |
7x2 |
|
| 4 u |
14 u |
9 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 9 is 18.
| |
Women |
Men |
Children |
| Number |
4 u |
14 u |
9 u |
| Value |
4 |
7 |
10 |
| Total value |
16 u |
98 u |
90 u |
Number of chocolates given away to women and children
= 16 u + 90 u
= 106 u
1 u = 530 ÷ 106 = 5
Number of adults
= 4 u + 14 u
= 18 u
Number of more adults than children
= 18 u - 9 u
= 9 u
= 9 x 5
= 45
Answer(s): 45
