At a party,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 5. Each man is given 4 chocolates and each woman is given 5 chocolates. Each accompanying child receives 7 chocolates. Given that only 360 chocolates are given away to men and children, how many more adults are there than children?
| Men |
Women |
Children |
| 2x4 |
1x4 |
| 3x1 |
5x1 |
|
| 3 u |
5 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 8 is 8.
| |
Men |
Women |
Children |
| Number |
3 u |
5 u |
4 u |
| Value |
4 |
5 |
7 |
| Total value |
12 u |
25 u |
28 u |
Number of chocolates given away to men and children
= 12 u + 28 u
= 40 u
1 u = 360 ÷ 40 = 9
Number of adults
= 3 u + 5 u
= 8 u
Number of more adults than children
= 8 u - 4 u
= 4 u
= 4 x 9
= 36
Answer(s): 36
