At a party,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 5 : 7. Each man is given 3 chocolates and each woman is given 4 chocolates. Each accompanying child receives 5 chocolates. Given that only 232 chocolates are given away to women and children, how many less men are there than women?
Men |
Women |
Children |
2x6 |
1x6 |
5x1 |
7x1 |
|
5 u |
7 u |
6 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 12 is 12.
|
Men |
Women |
Children |
Number |
5 u |
7 u |
6 u |
Value |
3 |
4 |
5 |
Total value |
15 u |
28 u |
30 u |
Number of chocolates given away to women and children
= 28 u + 30 u
= 58 u
1 u = 232 ÷ 58 = 4
Number of less men than women
= 7 u - 5 u
= 2 u
= 2 x 4
= 8
Answer(s): 8