At a party,
14 of the people are children. The remaining group of people is divided into women and men in the ratio of 5 : 7. Each woman is given 4 chocolates and each man is given 5 chocolates. Each accompanying child receives 7 chocolates. Given that only 192 chocolates are given away to women and children, how many more adults are there than children?
| Women |
Men |
Children |
| 3x4 |
1x4 |
| 5x1 |
7x1 |
|
| 5 u |
7 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 12 is 12.
| |
Women |
Men |
Children |
| Number |
5 u |
7 u |
4 u |
| Value |
4 |
5 |
7 |
| Total value |
20 u |
35 u |
28 u |
Number of chocolates given away to women and children
= 20 u + 28 u
= 48 u
1 u = 192 ÷ 48 = 4
Number of adults
= 5 u + 7 u
= 12 u
Number of more adults than children
= 12 u - 4 u
= 8 u
= 8 x 4
= 32
Answer(s): 32
