At a gathering,
13 of the people are children. The remaining group of people is divided into women and men in the ratio of 5 : 7. Each woman is given 2 sweets and each man is given 4 sweets. Each accompanying child receives 7 sweets. Given that only 140 sweets are given away to men and children, how many less women are there than men?
| Women |
Men |
Children |
| 2x6 |
1x6 |
| 5x1 |
7x1 |
|
| 5 u |
7 u |
6 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 12 is 12.
| |
Women |
Men |
Children |
| Number |
5 u |
7 u |
6 u |
| Value |
2 |
4 |
7 |
| Total value |
10 u |
28 u |
42 u |
Number of sweets given away to men and children
= 28 u + 42 u
= 70 u
1 u = 140 ÷ 70 = 2
Number of less women than men
= 7 u - 5 u
= 2 u
= 2 x 2
= 4
Answer(s): 4
