At a gathering,
25 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 5. Each man is given 2 candies and each woman is given 3 candies. Each accompanying child receives 6 candies. Given that only 564 candies are given away to women and children, how many less men are there than women?
Men |
Women |
Children |
3x8 |
2x8 |
3x3 |
5x3 |
|
9 u |
15 u |
16 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 8 is 24.
|
Men |
Women |
Children |
Number |
9 u |
15 u |
16 u |
Value |
2 |
3 |
6 |
Total value |
18 u |
45 u |
96 u |
Number of candies given away to women and children
= 45 u + 96 u
= 141 u
1 u = 564 ÷ 141 = 4
Number of less men than women
= 15 u - 9 u
= 6 u
= 6 x 4
= 24
Answer(s): 24